Water in a canal 30 dm wide and 12 dm deep, is flowing with a velocity of 100 km per hour. How much area will it irrigate in 30 minutes if 8 cm of standing water is desired?
Answers
Answer:
width 30dm =3m
depth =12dm=1.2m
water flow rate is 100km/h 100000/60m/min=50000/3m/min
water flow in 30min =50000x30/3=500000m
so volume of water 500000x3x1.2=1800000meter cube
Step-by-step explanation:
so volume=area x height
1800000= area x8/100
area =22500000 metrr square
2250hect
Given : Water in a canal 30 dm wide and 12 dm deep, is flowing with a velocity of 100 km per hour.
Breadth of a canal , b = 30 dm = 30/10 = 3 m
Height of a canal , h = 12 dm = 12/10 = 1.2 m
[1 dm = 1/10 m]
Speed of flow of water from canal = 100 km/h
= 100 × 1000 m/h = 100000 m/h
[1 km = 1000 m]
Length of water flows in 1 hour , l = 100000 m
Volume of water flowing from canal in 1 h = l × b × h
= 100000 × 3 × 1.2 = 360000 m³
Volume of water flowing from canal in 1 h = 360000 m³
Volume of water flowing from canal in 1/2 h (30 min) = ½ × 360000 = 180000 m³
Area for covering 8 cm or 8/100 m height of standing water = 180000/8 × 100 = 2250000 m²
Hence, it will irrigate 2250000 m² area in 30 minutes if 8 cm of standing water is desired.
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