Water in a canal, 30 dm wide and 12 dm deep, is flowing with a velocity
of 20 km per hour. How much area will it irrigate, if 9 cm standing water desired
Answers
Answer:
Velocity of water=20Km/h
Water in the canal forms a cuboid of breadth = 12dm=
10
12
m=1.2m
Height = 30dm=
10
30
m=3m
Length = Distance covered by water in 30 minutes
= Velocity of water × time
=20000×
60
30
=10000 m
Therefore,
Volume of water flown in 30 min = lbh=(1.2×3×10000)=36000 m
3
Suppose area irrigated be A m
2
. Then,
A×
100
9
= Volume flown in 30 minutes
A×
100
9
=36000
A=400000 m
2
Hence, area irrigated =400000 m
2
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Step-by-step explanation:
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Velocity of water=20Km/h
Velocity of water=20Km/hWater in the canal forms a cuboid of breadth
= 12dm= 12/10m =1.2m
Height = 30dm=
Height = 30dm= 10
Height = 30dm= 1030
Height = 30dm= 1030
Height = 30dm= 1030 m=3m
Height = 30dm= 1030 m=3mLength = Distance covered by water in 30 minutes
Height = 30dm= 1030 m=3mLength = Distance covered by water in 30 minutes = Velocity of water × time
Height = 30dm= 1030 m=3mLength = Distance covered by water in 30 minutes = Velocity of water × time =20000×
Height = 30dm= 1030 m=3mLength = Distance covered by water in 30 minutes = Velocity of water × time =20000× 60
Height = 30dm= 1030 m=3mLength = Distance covered by water in 30 minutes = Velocity of water × time =20000× 6030
Height = 30dm= 1030 m=3mLength = Distance covered by water in 30 minutes = Velocity of water × time =20000× 6030
Height = 30dm= 1030 m=3mLength = Distance covered by water in 30 minutes = Velocity of water × time =20000× 6030 =10000 m
Height = 30dm= 1030 m=3mLength = Distance covered by water in 30 minutes = Velocity of water × time =20000× 6030 =10000 mTherefore,
Height = 30dm= 1030 m=3mLength = Distance covered by water in 30 minutes = Velocity of water × time =20000× 6030 =10000 mTherefore,Volume of water flown in 30 min = lbh=(1.2×3×10000)=36000 m^3
3
3 Suppose area irrigated be A m^2
2 . Then,
2 . Then,A×
2 . Then,A× 100
2 . Then,A× 1009
2 . Then,A× 1009
2 . Then,A× 1009 = Volume flown in 30 minutes
2 . Then,A× 1009 = Volume flown in 30 minutesA×
2 . Then,A× 1009 = Volume flown in 30 minutesA× 100
2 . Then,A× 1009 = Volume flown in 30 minutesA× 1009
2 . Then,A× 1009 = Volume flown in 30 minutesA× 1009
2 . Then,A× 1009 = Volume flown in 30 minutesA× 1009 =36000
2 . Then,A× 1009 = Volume flown in 30 minutesA× 1009 =36000A=400000 m^2
2
2 Hence, area irrigated =400000 m^2
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