Water in canal, 6m wide and 1.5m deep Is flowing with a speed of 10km/hr. How much area will it irrigate in 30 minutes, if 8cm of standing water is needed?
Answers
Answer:
Canal is in the shape of cuboid , where,
Breadth =6 m
Height =1.5 m
Speed of canal =10 km/hr
Length of canal in 1 hour =10 km
Length of canal in 60 minutes =10 km
Length of canal in 1 minute =
60
1
×10 km
Length of canal in 30 minute =
60
30
×10=5km=5000 m
Now,
Volume of canal = length×breadth×height
= 5000×6×1.5 m3
Now,
Volume of water in canal = Volume of area irrigated
Volume of water in canal = Area irrigated × Height
5000×6×1.5 = Area irrigated ×
100
8
Area irrigated = 8 5000×6×1.5×100
Area irrigated = 562500 m2
Area irrigated =
10000
562500 hectares
Area irrigated = 56.25 hectares
Answer:
Given
It is given that the canal is the shape of a cuboid with dimensions as:
Breadth (b) = 6 m
Height (h) = 1.5 m
The speed of canal = 10 km/hr
Length of canal covered in 1 hour = 10 km
Find out
We need to find how much area will it irrigate in 30 minutes if 8cm of standing water is desired
Solution
Length of canal covered in 60 minutes = 10 km
Length of canal covered in 1 min = (1/60)x10 km
Length of canal covered in 30 min (l) = (30/60)x10 = 5km = 5000 m
We know that the canal is cuboidal in shape.
Formula
Volume of cuboid= l x b x h
Since canal is cuboidal shape
Volume of canal = lxbxh
= 5000x6x1.5 m3
= 45000 m3
Now,
Volume of water in canal = Volume of area irrigated
= Area irrigated x Height
So, Area irrigated = 56.25 hectares
∴ Volume of canal = lxbxh
45000 = Area irrigatedx8 cm
45000 = Area irrigated x (8/100)m
Or, Area irrigated = 562500 m2 = 56.25 hectares.