Question

Water is at the rate of 15km/h through a pipe of diameter 14 cm into a cuboid pond which is 50 m long and 44 m wide. In what time will the level of water in the pond rise by 21 m

Answer 1

Given diameter of cylinder = 14 cmTherefore radius of cylinder, r = 7 cmVolume of cylinder = πr2h cubic unitsVolume of water flowing through the cylindrical pipe in 1 hour at the rate of 15km/hr = (22/7) x (7/100) x (7/100) x 15000 = 231 cu m We know that volume of cuboid = lbh cubic units Therefore volume of water in the tank = 54 x 44 x (21/100) = 462 cu m Time taken = (462/231) = 2 hours

Answer 2

Step-by-step explanation:

Answer:

→ Time = 2 hours .

Step-by-step explanation:

Suppose, the level of water in the pond rises by 21 cm in 'x' hours.

→ Speed of water flowing through a pipe = 15 km/hr .

→ Diameter of the pipe = 14/100 m .

Then, Radius of the pipe (r) = 7/100 m .

∵ Volume of water flowing out of the pipe in 1 hour

= πr²h .

= (22/7) x (7/100) x (7/100) x 15000 .

= 231 m³ .

→

Volume of water flowing out of the pipe in 'x' hours = 231x m³.

∵ Volume of water in the cuboidal pond = lbh .

= 50 x 44 x (21/100) .

= 462 m³ .

∵ Volume of water flowing out of the pipe in 'x' hours = Volume of water in the cuboidal pond raised by 21 cm .

∵ 231x = 462 .

⇒ x = $\frac{462}{231}$

.

∴ x = 2 .

Therefore, the required time is 2 hours