Question

Water is filled in a container upto height 3m. A small hole of area 'a' is punched in the wall of the container at a height 52.5 cm from the bottom. The cross sectional area of the container is A. If a//A=0.1 then v^2 is (where v is the velocity of water coming out of the hole)

Answer 1

Given :

The height of water in the container = 3m

The height of hole from bottom = 52.5cm  = 0.525m

(a/A) = 0.1

To Find :

The square of the velocity of the flux

Solution :

• we know the relation

         Square of the velocity of flux(v²) = 2gh / [1 - (a/A)²]

• By substituting the values in the above relation

        v² =  2gh / [1 - (a/A)²]

            = 2×9.81×(3-0.525) / [1 - 0.1²]

            = 50 m² / s²

The square of the velocity of the flux is 50 m² / s²