Question

Water is filled in a right cylindrical tank with base radius 14 cm, such that water
level is 3 cm below the top. When an iron ball is dropped in the tank, 3003 cm of
water flows out. Find the radius of the ball.​

Answer 1

Radius of the ball is 10.5 cm.

Given

To find the radius of the ball.

Volume of water flows out = 3003 $cm^3$

Cylinder :

Volume of empty cylinder = π$r^2h$

Where,               radius ( r ) = 14 cm

                          height ( h ) = 3 cm

                                             = 22/7 × 14 × 14 × 3

        Volume of empty cylinder = 1848 $cm^3$.

Volume of iron ball = volume of empty cylinder + volume of water flows out

                                = 1848 + 3003

         Volume of iron ball = 4851 $cm^3$.

Sphere:

Volume of sphere = 4/3 π$r^3$

                                 4/3 π$r^3$ = 4851

                                          $r^3$ = 4851 × 3 × 7 / 22 × 4

                                              = 1157.625

                                            $r^3$ = 1157.625    

                                            r = $\sqrt[3]{1157.625}$

                                            r = 10.5 cm

Therefore, radius of the ball = 10.5 cm.

To learn more...            

1. brainly.in/question/13749505

2. brainly.in/question/14702654