Question

water is flowing at the rate of 15 km per hour through a pipe of diameter 14 cm into a cuboidal pond which is 50m long and 44m wide. By what level water will rise in2/3 hours of time​

Answer 1

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❏ Formula used:-

✦ CYLINDER✦

For a right circular cylinder of base radius r and height h,

$\sf\longrightarrow\boxed{ L.S.A=2\pi r h}$

$\sf\longrightarrow\boxed{ T.S.A.=2\pi r (r+h)}$

$\sf\longrightarrow \boxed{Volume=\pi r{}^{2}h}$

Where, •L.S.A.=Curved Surface area.

•T.S.A.=Total Surface Area.

✦ Cuboid ✦

For a cuboid of length l , breadth b and height h .

$\sf\longrightarrow\boxed{ Diagonal=\sqrt{l^{2}+b^{2}+h^{2}}}$

$\sf\longrightarrow\boxed{T.S.A.=2\times(lb+bh+hl)}$

$\sf\longrightarrow\boxed{ Volume=l\times b\times h}$

Where, •T.S.A.=Total Surface area.

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