Question

Water is flowing at the rate of 15 km per hour through a pipe of diameter 14 cm into a rectangular tank which is 50 m long and 44 m wide. Find the time in which the level of water in the tank will raise by 21 cm.

Answer 1

Here your answer goes

Step :- 1

In Cylinder ,

r = $\frac{d}2} cm$

r = $\frac{14}{2}$ cm

radius  = 7 cm = 0.7 m

l = 15 km

length = 15000 m

In Tank ,

l=50m

b=44m

h=0.21m

Step :- 2

Volume of the tank = l * b * h

⇒ 50 * 44 * 0.21

⇒ 462 $m^3$

Step :- 3

Height of the cylindrical pipe

$\frac{Vol.}{\pi r^2}$

⇒ $\frac{462}{\frac{22}{7}* (0.07)^2}$

⇒ $\frac{462}{0.0154}$

⇒ 30000 m

Time taken = $\frac{30000}{15000}$

= 2 hours

↓↓

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Answer 2

$<b>$ HEY MATE HERE IS YOUR ANSWER

$\rule {168} {2}$

We know that,


$\huge = > radius \: = \frac{diameter}{2}$

➡️ r = 14/2 = 7

Radius = 7 cm

In metres

Radius :- 0.7 m

Length = 15 km

In metres,

Length :- 15000 m

Now,

In tank

Length :- 50m

Breadth :- 44m

Height :- 0.21m

Now,

We know that,

Volume of tank :- L × B × H

➡️ 50 × 44×0.21

➡️ 462${m} ^{3}$

To find the height of cylindrical pipe :-

We know that,

$\huge = > \frac{volume}{\pi \: {r}^{2} } \\ \\ = > \frac{462}{ \frac{22}{7} \times 0.7 \times 0.7}$


$\huge = > \frac{462}{0.154}$


➡️ 30000m

$\huge = > time \: taken = \frac{30000}{15000} = 2$


➡️ 2 hours