Water is flowing at the rate of 15 km per hour through a pipe of diameter 14cm into a
rectangular tank which is 50 m long and 44 m wide. Find the time in which the level of
water in the tank will rise by 21 cm.
Answers
Answered by
0
Answer:
Step-by-step explanation:
Volume of cylinder= vol.of cuboid
(X) πrsq×h=LBH. (X is time)
On solving .
H= 15000msq.
R=0.14/2
And
L=50
B=44
H for cuboid is 0.21msq.
On equating x=2minutes.
Answered by
8
Heyy
⬇Here's ur answer
In cylinder,
r=7cm=0.7m
l=15km
=15000m
In tank,
l=50m
b=44m
h=0.21m
Vol.of water in tank=lbh
=50*44*0.21
=462m³
Height of cylindrical pipe=Vol. / πr²
=462/(0.07)²(22/7)
=462/0.0154
=30000m
Time = 30000/15000
= 2 hours
Hope it helps u
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