water is flowing at the rate of 15 km per hour through a pipe of diameter 14 cm into a rectangular tank which is 50 m long and 44 m wide, find the time in which the level of water in the tank will rise by 21 cm.
Answers
r=7cm=0.7m
l=15km
=15000m
In tank,
l=50m
b=44m
h=0.21m
Vol.of water in tank=lbh
=50*44*0.21
=462m³
Height of cylindrical pipe=Vol. / πr²
=462/(0.07)²(22/7)
=462/0.0154
=30000m
Time = 30000/15000
= 2 hours
Question:
→ Water is flowing at the rate of 15 km/h through a pipe of diameter 14 cm into a cuboidal which is 50m long and 44m wide. In what time will the level of water in pond raise by 21cm.
Answer:
→ Time = 2 hours .
Step-by-step explanation:
Suppose, the level of water in the pond rises by 21 cm in 'x' hours.
→ Speed of water flowing through a pipe = 15 km/hr .
→ Diameter of the pipe = 14/100 m .
Then, Radius of the pipe (r) = 7/100 m .
∵ Volume of water flowing out of the pipe in 1 hour
= πr²h .
= (22/7) x (7/100) x (7/100) x 15000 .
= 231 m³ .
→
Volume of water flowing out of the pipe in 'x' hours = 231x m³.
∵ Volume of water in the cuboidal pond = lbh .
= 50 x 44 x (21/100) .
= 462 m³ .
∵ Volume of water flowing out of the pipe in 'x' hours = Volume of water in the cuboidal pond raised by 21 cm .
∵ 231x = 462 .
⇒ x = 462/231 .
∴ x = 2 .
Therefore, the required time is 2 hours.
Hence, it is solved .
THANKS