Question

Water is flowing at the rate of 2.52 km/h through a
cylindrical pipe into a cylindrical tank, the radius
of whose base is 40 cm, if the increase in the level
of water in the tank, in half an hour is 3.15 m, find
the internal diameter of the pipe.
​

Answer 1

Answer:

Let the internal diameter of the pipe be r m.

water flows in 1 hour = 2.52 km.

Internal diameter of pipe = 4 cm.

Step-by-step explanation:

Answer 2

Answer:

diameter is 4

Step-by-step explanation:

Increase in the water level in half an hour = 3.25 m = 325 cm

Radius of the water tank = 40 cm

Volume of the water that falls in the tank in half an hour = πr2

h= 7/22 ×40×40×325=1634286 cu cm

Rate of the water flow = 2.52 km/hr

Length of water column in half an hour = 60(2.52×30)

=1.26 km=126000 cm

Let the internal diameter of the cylindrical pipe be d.

Volume of water that flows through the pipe in half an hour = π×( 2d)

2 ×126000

As we know that,

Volume of the water that flows through pipe in half an hour = Volume of water that falls in the cylindrical tank in half an hour

=7/22×( 2d )

2 ×126000=1634286

=7/22× 4d

2×126000=1634286

=d/2 ≈16 ⟹d=4cm

So, the internal diameter is 4