water is flowing in a horizontal pipe in area of cross section 0.03M2 with a velocity 2 m/sec at pressure 5x 10 power 4 N/m2 area of cross section reduce to 0.015 m2 what is the pressure at the smaller area of cross section
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Answer:
sing equation of continuity, we can find the velocity at another point. we have
a
1
v
1
=a
2
v
2
⇒(2×10
−2
)×2=0.01×v
2
⇒v
2
=4m/s
According to Bernoulli's theorem, for water at same height
ΔP=
2
ρ(v
1
2
−v
2
2
)
⇒ΔP=
2
1000×(2
2
−4
2
)
=−6000Pa
⇒P
2
−P
1
=−6000Pa
⇒P
2
−40000=−6000Pa
⇒P
1
=34000Pa=3.4×10
4
Pa
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