Math, asked by gg4, 4 months ago

Water is flowing through a cylindrical pipe of diameter 20 mm at the speed of 50 m/min into a
hemispherical tank of radius 1.5 m. In how much time will the tank be filled?​

Answers

Answered by ayushbro1234
1

Answer:

Diameter of circular end of pipe = 2 cm .. Radius ( 11 ) of circular end of pipe 2 m n = 0.01 m 200 Area of cross - section = nxrz ² 2 = TX * ( 0.01 ) 2 = 0.0001mm

Speed of water = 0.4 m / s = 0.4 x 60 = 24 metre / min Volume of water that flows in 1 minute from pipe - 24 x 0.0001mm = 0.0024mm Volume of water that flows in 30 minutes from pipe = 30 x0.00241m = 0.072 mm Radius ( r2 ) of base of cylindrical tank = 40 cm = 0.4 m Let the cylindrical tank be filled up to hm minutes

Volume of water filled in tank in 30 minutes is equal to the volume of water flowed out in 30 minutes from the pipe . :: TEX ( r22 ) xh = 0.0727 = ( 0.4 ) 2 xh = 0.072 = 0.16 h = 0.072 == 0.072 0.16 = h = 0.45 m = 45 cm Therefore , the rise in level of water in the half an hour is 45 cm .

Answered by yokeshps2005
5

Answer:

Radius of the pipe =220​ mm=10×101​ cm=1 cm

Speed of water =15 m/min=1500 cm/min

Volume of water that flows in 1 minute

=π×r2h=722​×1×1×1500 cm3/min=733000​ cm3/min

Radius of conical vessel =240​=20 cm;

Depth =45 cm

Therefore,

Capacity of the vessel =31​πr2h=31​×722​×(20)2×45=7132000​ cm3

Therefore, Time required to fill the vessel =Volume of water flowing per minuteCapacity of the vessel​

33000/7132000/7​ min =4 min

Step-by-step explanation:

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