Water is flowing through a cylindrical pipe of diameter 20 mm at the speed of 50 m/min into a
hemispherical tank of radius 1.5 m. In how much time will the tank be filled?
Answers
Answer:
Diameter of circular end of pipe = 2 cm .. Radius ( 11 ) of circular end of pipe 2 m n = 0.01 m 200 Area of cross - section = nxrz ² 2 = TX * ( 0.01 ) 2 = 0.0001mm
Speed of water = 0.4 m / s = 0.4 x 60 = 24 metre / min Volume of water that flows in 1 minute from pipe - 24 x 0.0001mm = 0.0024mm Volume of water that flows in 30 minutes from pipe = 30 x0.00241m = 0.072 mm Radius ( r2 ) of base of cylindrical tank = 40 cm = 0.4 m Let the cylindrical tank be filled up to hm minutes
Volume of water filled in tank in 30 minutes is equal to the volume of water flowed out in 30 minutes from the pipe . :: TEX ( r22 ) xh = 0.0727 = ( 0.4 ) 2 xh = 0.072 = 0.16 h = 0.072 == 0.072 0.16 = h = 0.45 m = 45 cm Therefore , the rise in level of water in the half an hour is 45 cm .
Answer:
Radius of the pipe =220 mm=10×101 cm=1 cm
Speed of water =15 m/min=1500 cm/min
Volume of water that flows in 1 minute
=π×r2h=722×1×1×1500 cm3/min=733000 cm3/min
Radius of conical vessel =240=20 cm;
Depth =45 cm
Therefore,
Capacity of the vessel =31πr2h=31×722×(20)2×45=7132000 cm3
Therefore, Time required to fill the vessel =Volume of water flowing per minuteCapacity of the vessel
33000/7132000/7 min =4 min
Step-by-step explanation: