Question

Water is flowing through a cylindrical pipe,of internal diameter 2 cm,into a cylindrical tank of base radius 40 cm,at the rate of 0.4 m/s,determine the rise in level of water in the tank in 1/2 of an hour.Also plzzz guide me on such type of problems as I get confused with them with proper steps.
How to find the height of the pipe?

Answer 1

volume of the pipe=volume of the tank

πr^2h=πr^2h

0.01^2(0.4)=0.4^2(h)

Answer 2

Answer:

Malayali ella..?

Step-by-step explanation:

radius of cylindrical pipe , r = 1cm

radius of cylindrical tank , R = 40cm

water is flowing through a cylinderical pipe into cylindrical tank at the rate of 0.4m/s or 40cm/s.

length of water through pipe , l= rate × time taken

= 40cm/s × 1/2 hr

= 40cm/s × 30 × 60

= 40 × 1800 cm

= 72000 cm

now, volume of water flows through pipe = volume of water rise in cylindrical tank..

or, πr² × l = πR² × h

or, (1cm)² × 72000 cm = (40cm)² × h

or, 72000cm³ = 1600 cm² × h

or, h = 720/16 cm = 45cm

hence, 45cm rise in the level of water in the rank in half an hour.

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