Question

Water is flowing through a horizontal pipe of varying cross-section. At a certain point where the velocity is 0.12 m/s, the pressure of water is 0.010 m of mercury. What is the pressure at a point where the velocity is 0.24 m/s?

Answer 1

Dear Student,

◆ Answer -

P2 = 1311 Pa

◆ Explanation -

# Given -

P1 = 0.01 m Hg = 1333 Pa

P2 = ?

v1 = 0.12 m/s^2

v2 = 0.24 m/s^2

# Solution -

For pipe of varying cross section -

P1 + ρgh + (1/2)ρv1^2 = P2 + ρgh + (1/2)ρv2^2

P1 + (1/2)ρv1^2 = P2 + (1/2)ρv2^2

1333 + 0.5×1000×0.12×0.12 = P2 + 0.5×1000×0.24×0.24

P2 = 1333 + 7.2 - 28.8

P2 = 1311 Pa

Therefore, pressure at a point of velocity 0.24 m/s is 1311 Pa.

Hope this helped you.