Question

Water Is flowing through horizontal tube in a streamlined of non uniform cross-section . The speed of water is 30cm /s at a place where pressure is 10 cm ( of water) . Calculate the speed of water at the other place where the pressure is half of that at the first place

Answer 1

The relationship between the pressure and velocity is given by

12ρv12+P1=12ρv22+P2⇒12ρv12+ρgh1=12ρv22+ρgh2⇒v12+gh1=v22+gh2⇒302+9.8×10=v22+9.8×5⇒v22=949⇒v2=30.8

So velocity will be 30.8 m/s