Math, asked by anindyarastogi764, 11 months ago

Water is pouring into a tank at a constant rate when the tank is full 10 pumps of equal capacity empty the tank in 12 hours by 15 pounds of the same capacity empty the tank in 6 hours find the time in which 25 pumps of the same capacity take to empty the tank if the tank is initially full

Answers

Answered by knjroopa
3

Step-by-step explanation:

Given Water is pouring into a tank at a constant rate when the tank is full 10 pumps of equal capacity empty the tank in 12 hours while 15 pumps of the same capacity empty the tank in 6 hours find the time in which 25 pumps of the same capacity take to empty the tank if the tank is initially full

  • Suppose the pump is being emptied it will be positive work, so let this be x in 12 hrs.
  • Therefore one pump will empty in 1/x hrs.
  • To fill the tank let it be y work. So to fill it will be negative, so -y.
  • Therefore it will fill in -1/y hrs.
  • So 1/x – 1/y = 1/12
  • So 10 pumps will empty the tank
  • So 10/x – 1/y = 1/12 -------------1
  • Similarly for 15 pumps we get
  • 15/x – 1/y = 1/6 ------------------2
  • We need to find for 25/x – 1/y = ?
  • So subtracting eqn 2 – 1 we get
  • 5/x = 1/12, x = 60
  • Consider eqn 2 we get
  • -1/y = 1/6 – 15/x
  • -1/y = 1/6 – 15/60
  • -1/y = 1/6 – 1/4
  • -1/y = - 1/12
  • Therefore 25/x – 1/y
  •              = 5/12 – 1/12
  •             = 4/12
  •            = 1/3  

So it will take 3 hrs to empty the tank.

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