Water is pouring into a tank at a constant rate when the tank is full 10 pumps of equal capacity empty the tank in 12 hours by 15 pounds of the same capacity empty the tank in 6 hours find the time in which 25 pumps of the same capacity take to empty the tank if the tank is initially full
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Given Water is pouring into a tank at a constant rate when the tank is full 10 pumps of equal capacity empty the tank in 12 hours while 15 pumps of the same capacity empty the tank in 6 hours find the time in which 25 pumps of the same capacity take to empty the tank if the tank is initially full
- Suppose the pump is being emptied it will be positive work, so let this be x in 12 hrs.
- Therefore one pump will empty in 1/x hrs.
- To fill the tank let it be y work. So to fill it will be negative, so -y.
- Therefore it will fill in -1/y hrs.
- So 1/x – 1/y = 1/12
- So 10 pumps will empty the tank
- So 10/x – 1/y = 1/12 -------------1
- Similarly for 15 pumps we get
- 15/x – 1/y = 1/6 ------------------2
- We need to find for 25/x – 1/y = ?
- So subtracting eqn 2 – 1 we get
- 5/x = 1/12, x = 60
- Consider eqn 2 we get
- -1/y = 1/6 – 15/x
- -1/y = 1/6 – 15/60
- -1/y = 1/6 – 1/4
- -1/y = - 1/12
- Therefore 25/x – 1/y
- = 5/12 – 1/12
- = 4/12
- = 1/3
So it will take 3 hrs to empty the tank.
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