Water is snowing at the rate of 2.52 km/hr through a cylindrical pipe into a cylindrical tank, the radius of whose base w 40 cm if the
Answers
Explanation:
Increase in the water level in half an hour = 3.15 m = 315 cm
Radius of the water tank = 40 cm
Volume of the water that falls in the tank in half an hour = πr²h
= 22/7*40*40*315
= 1584000 cu cm
Rate of the water flow = 2.52 km/hr
Length of water column in half an hour = (2.52*30)/60
= 1.26 km = 126000 cm
Let the internal diameter of the cylindrical pipe be d.
Volume of water that flows through the pipe in half an hour = π*(d/2)²*126000
As we know that,
Volume of the water that flows through pipe in half an hour = Volume of water that falls in the cylindrical tank in half an hour
⇒ 22/7*(d/2)²*126000 = 1584000
⇒ 22/7*d²/4*126000 = 1584000
⇒ d² = 16
⇒ d = √16
⇒ d = 4
So, the internal diameter of the pipe is 4 cm
Answer.
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Answer:
Please complete the question and please give either the radius of the pipe or the height of the water column in the tank.
Hope the explanation part part would help you.
Insert the radius or the height in the given areas.
The answer couldn't get completed because of the incomplete question.
Explanation:
speed of the water=2.52km/hr
=2.52×5/18=0.7m/sec
therefore through 0.7m pipe water flows in 1 sec.
or the length of the pipe is 0.7m or 7cm
let the radius of pipe be r cm
therefore the volume of water in the pipe is =pi×r^2×70
the radius of the tank is 40cm
let the height of the water column be h
cm
then the volume of the tank= pi×40×40×h
to find the radius of the pipe or the height of the tank the equation will be
= volume of the tank / volume of the pipe