Question

Water rises in a capillary tube to a height of 2 cm. In another
capillary tube whose radius is one third of it, how much the
water will rise? If the first capillary tube is inclined at an
angle of 60° with the vertical then what will be the position
of water in the tube.​

Answer 1

Answer:

4 cm

Explanation:

We know :

h = 2 S cos Ф / r ρ g

= > r h =  2 S cos Ф / ρ g = constant .

= > r₁ h₁ = r₂ h₂

= > h₂ = h₁ r₁ / r₂

Putting values here we get :

= > h₂ = h r / r / 3

=  h₂ = 3 h r / r

= > h₂ = 3 h

= > h₂ = 3 × 2 cm

= >  h₂ = 6 cm .

Now if h₃ be the height of liquid in capillary in the inclined position , the vertical height will remain same :

= > h₃ = h / cosФ

= > h₃ = 2 / 1 / 2 cm

= > h₃ = 4 cm

Therefore , we get required answer.