Question

water rises to a height of 6.6cm in a a capillary tube of radius 0.2mm. the surface tension of water(g=10ms-2)
1)6.5 into 10-3N/M
2)6.5 into 10-2N/M
3)6.5 into 10-4N/M
4)6.5 into 10-1N/M

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Answer 1

Answer:

6.5 into 10-4N/M

Explanation:

I think so this will be answer

Answer 2

Concept Introduction: Surface Tension,

Answer: Option 2, (6.5×$10^{-2}$N/M) is correct answer,

Given that in question:

                    Height(h)=6.6cm, or 6.6×$10^{-2}$m,  

                    Radius(r)=0.2mm, or 0.2×$10^{-3}$m,

                    gravity(g)=10$ms^{-2}$,

                    Density(ρ)=$10^{3}$$kgm^{-3}$, we know that,

             contact angle(θ)=0, then cos0=1, we know that,

We have to find: the value of surface tension,

Explanation:

• In this question we have to find surface tension (s) we simply using formula to calculate the value of s,

                  →              h=2Scosθ/rρg,

                  →              S= rρgh/2cosθ,

              S=0.2×$10^{-3}$m×$10^{3}$$kgm^{3}$×10$ms^{-2}$×6.6×$10^{-2}$m/2×1,

     after calculation above equation we get, S=6.5×$10^{-2}$N/M,

     Hence, the correct answer of the question is option 2,