Wavelength of a photon is 4000 A. It's energy will be..
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Energy (E) of a photon = hc/λ
Where,λ = wavelength of light = 4000 pm = 4000 ×10–12 m = 4x 10-9 m
c = velocity of light in vacuum = 3 × 108 m/s
h = Planck’s constant = 6.626 × 10–34 Js
thefore the energy of photon (E)
= 6.626 × 10–34 Js X 3 × 108 m/s / 4x 10-9 m = 4.965 x 10-16 J
Now 4.965 x 10-16 J is the energy of = 1 photon
Therefore 1 J will be the energy of = 1/4.965 x 10-16 J = 2.014 x 1015photons
Where,λ = wavelength of light = 4000 pm = 4000 ×10–12 m = 4x 10-9 m
c = velocity of light in vacuum = 3 × 108 m/s
h = Planck’s constant = 6.626 × 10–34 Js
thefore the energy of photon (E)
= 6.626 × 10–34 Js X 3 × 108 m/s / 4x 10-9 m = 4.965 x 10-16 J
Now 4.965 x 10-16 J is the energy of = 1 photon
Therefore 1 J will be the energy of = 1/4.965 x 10-16 J = 2.014 x 1015photons
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Answer:
4.97 × 10^-19 \ "Joule"
Explanation:
E = (hc)/λ
E = (hc)/λ = (6.626 × 10^-34\ "J s" × 3 × 10^8\ "m/s")/(4000 × 10^-10\ "m")
E = 4.97 × 10^-19 \ "Joule"
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4.97 × 10^-19 \ "Joule"
Explanation:
E = (hc)/λ
E = (hc)/λ = (6.626 × 10^-34\ "J s" × 3 × 10^8\ "m/s")/(4000 × 10^-10\ "m")
E = 4.97 × 10^-19 \ "Joule"
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vamshi71:
please mark as brainliest please please
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