Question

Wavelength of a photon radiation containing energy E is 4000 Angstrom then wavelength of an other photon radiation containing energy 0.5E will be-

Answer 1

Answer:

The wavelength of the other photon radiation containing energy 0.5E will be 8000 Angstrom.

Explanation:

Given data:  

The energy of radiation = E

Wavelength, v = 4000 Angstrom

To find: wavelength of photon with energy radiation 0.5E.

We know,  

E = hv ……. (i)

Here, E: energy of radiation

    h: Plank’s constant

     v: frequency

also, frequency = (velocity of the light) / (wavelength)  

i.e., v = c / λ ……(ii)

combining equation (i) & (ii)

∴ E = (h c) / λ

Or, E = (hc) / 4000 …… (iii)

Now, we are required to find the wavelength “λ₁” of photon with energy of radiation “E₂” as "0.5E". h and c remains constant.

We can write,

∴ E₂ = (hc) / λ₁

Or, 0.5 * E = (hc) / λ₁ ……. (iv)

Equating (iii) & (iv), we get

0.5 * E = (hc) / λ₁

Or, 0.5 * {(hc) / 4000} = (hc) / λ₁

Or, λ₁ = 4000 * 2

Or, λ₁ = 8000 Angstrom

Answer 2

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