Question

wavelength of an electron which is accelerated by 37.5V potential difference

Answer 1

we have standard form lamda=12.24÷√v
from that 12.24÷√37.5=12.24/6.123=1.99902A°

Answer 2

we know,
Lamda = 12.24 ÷ root v
from that,
12.24÷ root 37.5
=12.24/6.123=1.99902A degree