Question

wavelength of certain radiation is 6625 degrees A THEN no of quantas present in 1j of energy of that radiation is

Answer 1

From Planck’s Equation energy of a photon

E=hc/l

Energy of 1 photon = (6.62 × 10^-34 )×(3 × 10^8)/(6625 × 10^-12)

=>2.9977 * 10^(-17) Joules

SO,

No, of photons required for 1 J = 1/(2.997 * 10^(-17)

=> 3.3366 * 10^16 Photons