Question

Wavelength of light incident on a single slit of width
0.1 mm is 6000 Å. Distance of screen from slit is 100
cm. Then the width of central maximum is
cm.
(Chp.10)
(a) 0.6 (b) 1.2 (C) 2.4 (d) 3.0​

Answer 1

Answer:

You Know

First Minima Occurs at

sinThita = Lemda/a

Y/D = Lemda /a

Y = Lemda D /a

Central Maxima - 2Y

CM = 2Lemda D/a

CM = 2× 6 × 10^-7 × 1 / 10^-4

CM = 12 × 10^-3meter

in cm

CM = 1.2cm

Explanation:

Thanks for Reading

Dr Harsh