Question

ways to make your own indicators to test for the presence of calcium fluoride

Answer 1

Simplifying5x + -3(4) = 15Multiply -3 * 45x + -12 = 15Reorder the terms:-12 + 5x = 15Solving-12 + 5x = 15Solving for variable 'x'.Move all terms containing x to the left, all other terms to the right.Add '12' to each side of the equation.-12 + 12 + 5x = 15 + 12Combine like terms: -12 + 12 = 00 + 5x = 15 + 125x = 15 + 12Combine like terms: 15 + 12 = 275x = 27Divide each side by '5'.x = 5.4Simplifyingx = 5.4