Math, asked by anushamidatana1847, 1 year ago

Wch is a recursive formula for the sequence 99.4, 0, –99.4, –198.8, where f(1) = 99.4? f(n + 1) = f(n) + 99.4, n ≥ 1

Answers

Answered by pathalavathvijay
2
10+ 5
10 + 5 \sqrt{5 + 2 \sqrt{7 +  \sqrt{35} } }
Answered by amorycryptic
2

Answer:

f(n + 1) = f(n) – 99.4, n ≥ 1

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