Question

WE-11: A calorimeter of water equivalent
83.72 Kg contains 0.48 Kg of water at
35°C. How much mass of ice at 0°C should
be added to decrease the temperature of
the calorimeter to 20°C.
(S.=4186J/Kg-K and Lice = 335000J/Kg)​

Answer 1

Answer:

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Answer 2

83.72×15×4186+0.48×15×4186

=84.20×15×4186J

=5286918J

m(535000)+m(20)(4186)=5286918

m=12.62kg