Question

-We are given that triangle PQR is an isosceles triangle in which PQ = PR .
-Since the base angles of an isosceles triangle are equal,
angle PQR = angle PRQ
-And we are given that
angle MRQ = angle NQR
-And we know that QR = QR
-triangles QNR is congruent to triangles RMQ - ASA - angle side angle

i got 2/4, what's wrong with the answer?

Answer 1

Answer:

Step-by-step explanation:

GIVEN -

PQR is an isoscles Δ

PQ = PR

M, N are points on PQ & PR

∠MRQ = ∠RMQ

TO PROVE THAT

ΔQNR ≅ ΔRMQ,

MR = QN ( diaganals bisect )

∠MRQ = ∠NQR ( given )

QR = QR ( common base )

⇒ ΔQNR ≅ ΔRMQ by SAS rule

i dont think its correct but i tried it.

PROOF

in ΔQNR & ΔRMQ

Answer 2

Given: Here we have given PQR is an isoscles Δ

To find: Here we have to prove that traingles QNR and RMQ are congurent

Solution:

Here we have

PQ = PR

M, N are points on PQ & PR

∠MRQ = ∠RMQ
We have diaganals bisectors

MR = QN

Here we have given

∠MRQ = ∠NQR

Also we have common base QR

QR = QR

⇒ ΔQNR ≅ ΔRMQ by SAS rule

Final answer:

Hence ΔQNR ≅ ΔRMQ