Question

We are going to mix a 10% alcohol solution with some 30% alcohol
solution. The goal is to make 20 liters of 16% solution. What is the
amount of each that needs to be used to achieve this.
O (14 liters of 10% solution; 6 liters of 30% solution)
O (6 liters of 10% solution: 9 liters of 30% solution)
O (14 liters of 10% solution: 9 liters of 30% solution)
O (9 liters of 10% solution; 6 liters of 30% solution)
O (6 liters of 10% solution; 14 liters of 30% solution)​

Answer 1

Answer:

A

Step-by-step explanation:

coz 16 is near to 10 and far from 30 so a solution of 10 % must be added in greater amount and the sum should be equal to 20 liters

Answer 2

Answer:

OPTION A (14 liters of 10% solution; 6 liters of 30% solution)

Step-by-step explanation:

Our goal is to make 20 liters of 16% solution.

Total 20 litres

Option A

14 litre + 6 Litre = 20 Litre

Option B

6 litre + 9 Litre = 15 Litre

Option C

14 litre + 9 Litre = 23 Litre

Option D

6 litre + 14 Litre = 20 Litre

So it can be easily seen that Option A and Option D satisfies total 20 Litres.

Now,

Our goal is to make 20 liters of 16% solution.

So 16 is very near to 10 and very far to 30

So we have to take little amount of 30% alcohol and greater amount amount of 10% alcohol.

Only Option A satisfies this.