We divide Rso. 300 into two parts such that 1/2 of the first and 1/3 of the second arweek equal. Find the difference of two parts.
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10 is the difference between the two parts.
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We can solve this problem by forming a pair of linear equations in two variables and then solving them for the values.
Let the first part be 'x' and the other part be 'y'.
Then, x+y=300
Also,
⇒ 3x= 2y
⇒x=
Putting this in the first equation:
we get, +y=300
⇒
⇒5y= 900
⇒y= 180
and, x = 300- 180
⇒x= 120
∴ The differnce between the two parts is 60.
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