we have 100 litres of a mixture of milk and water which is 10% water. How much more pure milk should be added so that the new mixture has only 5% water?
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Answer:
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A mixture of milk and water, sound more like chemistry question, but when yu read the question careful and analysed it , yu find out that yu just need a simple basic mathematical approach .
The mathematical appraoch for this question is this:
Initial volume of mix =100l
Initial volume of water in mix = 10%(100l) = 10l
Initial volume of milk in mix=90%(100l)=90l
Let the unknown quantity (liters) of milk added be x
Remember it was just only milk that was added, no water was further added.hence the volume of water remains constant.
Hence:
New volume of mix = (100+x)liters
Volume of water in newmixture=5%(100+x)
Volume of milk in new mixture=95%(100+x)
Hence finding value of x(unknown liters of milk added) ?
Volume of water remains unchanged
Vol of water in initial mix =vol of water in new mixture
10l = 5% (100+x)l
10 =0.05(100+x)
10 = 5 +0.05x
10–5 =0.05x
5 =0.05x
x =5/0.05 = 100liters
Hence the volume of milk added to the mixture is 100liters.
Alternatively :
We can also state that since the initial volume of milk in mixture is 90l, then the new volume will be (90+x)liters.
Hence: (90+x)l = 95%(100+x)l
90+x = 0.95(100+x)
90 +x =95 + 0.95x
x-0.95x =95–90
0.05x =5
x = 5/0.05 = 100 liters
Hope this help.
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