Question

We have a channel with a 1 mhz bandwidth. The snr for this channel is 63. What are the appropriate bit rate and signal level?

Answer 1

Answer:

The bit rate will be 6 Mbps and the signal level is 2.B log2 M[bps]

Explanation:

As the problem says, the bandwidth is 1 mhz.

Now we all know that according to the Shannon formula

c = B log2(1 + S/N) [ where C= the bit rate,  B = bandwidth, S = average signal power and N = average noise power]

= 10^6 log2(1 + 63)

= 6Mbps.

Then use the Nyquist formula to find the number of signal levels.

signal level = 2.B log2 M[bps] [ where B is the bandwidth]