we have a polynomial p (x)=-3x^2+kx^2-8x+10 2 is a zero of p(x). find k
Answers
Answered by
2
Answer:
given ,
p(x) = 3x^2 + kx^2-8 x +10
2 is a zero of the polynomial
therfore p(2) = 3 (2^2) +k (2^2)- 8x2 +10=0
= 3(4) + k(4) -16+10= 0
= 12 +4k-16+10=0
= 6+4k = 0
4k= -6
k= -6/4
k = -3/2
Similar questions