Question

We have a polynomial p(x)=-3x+kx²-8x+10
2 is a zero of p(x)​

Answer 1

Answer:

k=0

Step-by-step explanation:

p(x)=-3x+kx²-8x+10

=kx²-5x+10

2 is a zero of p(x)

then p(2)=0

k(2)²-5*2+10=0

4k-10+10=0

k=0

Answer 2

Question:

We have a polynomial $p(x)=-3x+kx^2-8x+10$

2 is a zero of p(x)​

Answer:

K = 3

Step-by-step explanation:

Polynomial = $-3x+kx^2-8x+10$

⇒$p(x)=-3x+kx^2-8x+10$

Here they given p(x)= 2

⇒p(2)=$-3(2)+k(2)^2-8(2)+10$

⇒$p(2)=-6+4k-16+10$

⇒$4k-22+10$

⇒$4k-12$

⇒$4k=12$

⇒ $k=\frac{12}{4}$

⇒$K = 3$

Hence your answer is K is 3