We have : Degree C=5F-160
what is the temperatur in celsius of the temperature is 86degree F.
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C/5=(F-32)/9
=>C/5=(86-32)/9
=>C/5=54/9
=>C/5=6
=>C=6*5
=>C=30 degree
=>C/5=(86-32)/9
=>C/5=54/9
=>C/5=6
=>C=6*5
=>C=30 degree
Answered by
0
C=5/9(F-32)
F=86 F
then, C= 5/9(86-32)
=5/9X54
30 C.
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