Question

we know that -3,2are the zero of polynomial x*x (a+1)+b fibd the value of a and b​

Answer 1

Answer:

a = -1 and b = 0

Step-by-step explanation:

taking x = - 3;

3*3(a+1) + b = 0

9a + b + 9 = 0 suppose this is eqn 1st

now taking x = 2;

2*2(a+1)+ b = 0

4a + b +4 = 0 suppose this is eqn 2nd

by solving these equation we'll get

a = -1 and b = 0;

thanks

Answer 2

Question:

-3, 2 are the zeroes of the polynomial x² + (a+1)x + b find the value of a and b

Answer:

a = -2

b = -6

Step-by-step explanation:

Let, α = -3 and β = 2

We know that,

$\alpha + \beta = \frac{b}{a} \\ \alpha \beta = \frac{c}{a}$

Here, a = 1, b = a+1, c = b

$- 3 + 2 = \frac{a + 1}{1} \\ - 1 = a + 1$

a = -1 - 1 = -2

$- 3 \times 2 = \frac{b}{1} \\ - 6 = b$

$\therefore{ \boxed{a = - 2 : b = - 6}}$