We know that A➖ B whole square is equal to B➖ A whole square but if we remove the square from both side then A➖ B doesn't equal to B➖ A.why explain
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Argument : - ( a- b) ² = ( b -a ) ² then after removing the square ,are resultants equal?
We know that;
a = - ( - a)
(a - b)²= [ - ( b- a) ] ²
( a - b ) ² = ( b - a) ²
Applying square root on both sides we get
± (a - b) = ± ( b - a)
=> + ( a - b) = - ( b - a) => a-b = a-b
=> -( a - b) = + ( b - a ) => b - a = b -a
Hence,
The equality of ( a - b) ² = ( b - a) ² is correct.
We know that;
a = - ( - a)
(a - b)²= [ - ( b- a) ] ²
( a - b ) ² = ( b - a) ²
Applying square root on both sides we get
± (a - b) = ± ( b - a)
=> + ( a - b) = - ( b - a) => a-b = a-b
=> -( a - b) = + ( b - a ) => b - a = b -a
Hence,
The equality of ( a - b) ² = ( b - a) ² is correct.
HappiestWriter012:
Thanks! Hopefully it helps
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