we know that i^² = (-1)
soln:
i^² = i × i
=√(-1) × √(-1)
=√{(-1) × (-1)}
=√1
=1
how it is possible?
Answers
Answered by
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see,
i=√-1
i²=i×i
=-1
therefore i =√-1 and
i²=±1=-1 is always fixed value
i³=i×i×i
=-i
=√-1×√-1×√-1×√-1
=1
..
..
..
thank u
i=√-1
i²=i×i
=-1
therefore i =√-1 and
i²=±1=-1 is always fixed value
i³=i×i×i
=-i
=√-1×√-1×√-1×√-1
=1
..
..
..
thank u
sakthikrish435p0cir9:
u know complex number?
ya
y...
in complex number,, are they assigned any value for i ?
ur asking the question as the value of 'I'm is present in complex number chapter yeas it is present
r u sure?
Ya
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