we know that,if 7=2^x then x=log2^7.then what is the value of 2^log2^7?justify u r answer
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2^Log2^7
=2^x (since x=log2^7)
=7. (Since 2^x=7)
=2^x (since x=log2^7)
=7. (Since 2^x=7)
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