Question

we must be added to each term of the ratio 49:68 so that it becomes 3:4​

Answer 1

read. equation -> 49 +x /68+x = 3/4

-> 204 +3x = 196 + 4x

-> x = 204 - 196

-> x = 8

Hence, the required number is 8.

HOPE I COULD HELP !!!

Answer 2

$\textbf{\underline{\underline{Answer :-}}}$

The number 8 should be added.

$\textbf{\underline{\underline{Explanation :-}}}$

$\textsf{\underline{\underline{Given :}}}$

The Ratio = 49:68

Required Ratio = 3:4

$\textsf{\underline{\underline{To find :}}}$

Number added to 49:68 to get 3:4.

$\textsf{\underline{\underline{Solution :}}}$

The corresponding fractions of the Ratio = $\sf{\dfrac{49}{68}}$ and $\sf{\dfrac{3}{4}}$

Consider the number as x

$\sf{\implies} \: \dfrac{49 + x}{68 + x} = \dfrac{3}{4}$

$\sf{\implies} \: 4(49 + x) = 3(68 + x)$

$\sf{\implies} \: 196 + 4x = 204 + 3x$

$\sf{\implies} \: 4x - 3x =204 - 196$

$\sf{\implies} \: x = 8$

${\boxed{\boxed{\sf{x = 8}}}}$

$\therefore$ The number 8 should be added to each term to make the ratio 49:68 turn into 3:4.

$\textbf{\underline{\underline{Verification :-}}}$

$\sf{\implies} \: \dfrac{49 + 8}{68 + 8} = \dfrac{3}{4}$

$\sf{\implies} \: \dfrac{57}{76} = \dfrac{3}{4}$

Reduce the fraction by dividing it by 19.

$\sf{\implies} \: \dfrac{3}{4} = \dfrac{3}{4}$

Both sides are equal.

$\therefore$ The number 8 should be added to each term to make the ratio 49:68 turn into 3:4.