Question

We need a dataword of at least 15 bits. Calculate values of k and n that satisfy
this requirement.

Answer 1

Answer:

Here ishow you calculate a dataword of atleast 15 bits

Explanation:

a. Let m = 1 k = 2m −1 − m = 21 −1 − 1 = 0 (not acceptable)

b. Let m = 2 k = 2m −1 − m = 22 −1 − 2 = 1 (not acceptable)

c. Let m = 3 k = 2m −1 − m = 23 −1 − 3 = 4 (not acceptable)

d. Let m = 4 k = 2m −1 − m = 24 −1 − 4 = 11 (not acceptable)

e. Let m = 5 k = 2m −1 − m = 25 −1 − 5 = 12 (not acceptable)

f. Let m = 6 k = 2m −1 − m = 26 −1 − 6 = 13 (not acceptable)

g. Let m = 7 k = 2m −1 − m = 27 −1 − 7 = 14 (not acceptable)

h. Let m = 5 k = 2m −1 − m = 28 −1 − 8 = 15 (acceptable)

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Data can be thought of as the plural version of datum. Data (originally a Latin plural) is not used like a typical count noun with cardinal numbers and can be plural with such plural determiners as these and many or as a mass noun with a verb in the singular form. Datum actually can also be a count noun with the plural datums (see usage in datum article) that can be used with cardinal numbers (e.g., "80 datums").

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