we should be to taken out from p^2+q^2+2pq+10 to obtain -2p^2-2q^2+7pq+10
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Answer:
LET THE NUMBER BE x
- So,The equation would be p^2+q^2+2pq+10 - x = -2p^2-2q^2+7pq+10
- p^2+q^2+2pq+10 - (-2p^2-2q^2+7pq+10) = x
- p^2+2p^2+q^2+2q^2+2pq-7pq+10-10 = x
- THUS,THE VALUE OF x is 3p^2+3q^2-5pq
TEERTH BAKSHI
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