Weight of 3×10^5 molecule of H2o is
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molar mass :- mass of the one mole of the substance.
molar mass of the H2O = 2+16 = 18g/mol
one mole of any substance contains 6.022 × 10^23 molecules.
18 gram contains = 6.022×10^23 molecules
" X " grams contains = 3×10^5 molecules
[ cross multification ]
X = 18 × 3 × 10^5/6.022×10^23
X = 54×10^5/6.022×10^23
X = 8.9671 × 10^5-23
X = 8.97 × 10^-18 g
so mass of the 3 × 10^5 molecules of H2O is 8.97 × 10^-18 grams.
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onother method
one mole of any substance contains exactly avogadro number of molecules.
molecules = number of moles × 6.022 × 10^23
molecules = mass/molar mass × 6.022 × 10^23
3×10^5 = mass/18 × 6.022×10^23
3×10^5×18 = mass × 6.022×10^23
54 × 10^5 = mass × 6.022×10^23
mass = 54×10^5/ 6.022×10^23
mass = 8.97 × 10^5-23
mass = 8.97 × 10^-18 g
molar mass of the H2O = 2+16 = 18g/mol
one mole of any substance contains 6.022 × 10^23 molecules.
18 gram contains = 6.022×10^23 molecules
" X " grams contains = 3×10^5 molecules
[ cross multification ]
X = 18 × 3 × 10^5/6.022×10^23
X = 54×10^5/6.022×10^23
X = 8.9671 × 10^5-23
X = 8.97 × 10^-18 g
so mass of the 3 × 10^5 molecules of H2O is 8.97 × 10^-18 grams.
__________________________________________________
onother method
one mole of any substance contains exactly avogadro number of molecules.
molecules = number of moles × 6.022 × 10^23
molecules = mass/molar mass × 6.022 × 10^23
3×10^5 = mass/18 × 6.022×10^23
3×10^5×18 = mass × 6.022×10^23
54 × 10^5 = mass × 6.022×10^23
mass = 54×10^5/ 6.022×10^23
mass = 8.97 × 10^5-23
mass = 8.97 × 10^-18 g
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