Question

Weight of a body decreases by 1.5 % when it is raised to a height h above the surface of the earth and the same body is taken to same depth h in a mine its weight will show

Answer 1

hi

Weight= mg

As mass everywhere remains same, so there will be change in the value of g.

g'= g - 1.5%g = 98.5/100g

For height

g'= g(1-2h/R)

98.5/100g = g(R-2h)/R

98.5R = 100R - 200h

h = (1.5/200)R = 0.0075R

For depth

g'= g(1-d/R). [d=h=0.0075R]

g'= g(1-0.0075)

g'= 10 * 0.9925. [g=10]

g'= 9.9

%change = (∆g/g) *100

∆g= 10- 9.925= 0.075

℅ = (0.075/10)*100

=0.75℅

HOPE THIS WAS HELPFUL

Answer 2

Answer:  

But since h<<<R

there will be a decrese of g by 0.75%