what acceleration will stop the car exactly at the stop sign
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S=36 dispacment
u=12 initial velocity
v=0 final velocity
0-144=2a×36
a=-2
hope it helps comment if you have any problem
u=12 initial velocity
v=0 final velocity
0-144=2a×36
a=-2
hope it helps comment if you have any problem
Answered by
4
hope it help
thank u
thank u
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