Question

What amount of heat is required to convert

10gm of ice at 0

0c to water at 10

0c? Given

Latent heat of fusion 80 cal/gm and Specific heat Capacity of Water is 4.2 J/gm/

0c.​

Answer 1

Answer:

the heat required is MLf + Mc∆ T. here first 10 gram of ice at zero degree to be converted to 10 gram water at zero degree= 10×80= 800 calories. Now 10 gram of this water at zero degree should be converted to 10 gram at 10 degrees = Mc∆ T = 10×1 ×(10-0) =100 calories. ( here I have taken specific heat of water as 1 cal / gram. So all together we need = 900 calories. please mark as brainliest