Question

what amount of lime stone having 40% impurities is required to produce 5.6L CO2 gas at STP by reaction with excess HCl

Answer 1

Your answer is shown below by following process :-

Equation :-

$caco_{3} \: + \: 2 \: hcl \: \: \: -> \: \: \: cacl_{2} \: + \: h_{2}o \: + \: co_{2}$

$mass \: of \: co_{2} \: formed \: = \: \frac{44 \: \times 5600}{22400} \: g \: = \: 11g$

According to Gay-Lussac law,

$mass \: of \: lime \: stone \: (caco_{3}) \: including \: impurities \: = \: 11g$
Therefore,

$mass \: of \: lime \: stone \:without \: impurities \: = \: \frac{60}{100} \: \times \: 11 \: = \: 6.6g$
Hence, amount of Lime Stone is 6.6g .