What amount of Na2CO3 is dissolve in 250 ml water to prepare semi molar solution?☺
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Answer:
12.875 g.
Explanation:
We get that the number of moles will be equal to:-
Moles equal to its concentration x volume (n=cv)
=0.5mol/dm3 x (250/1000)dm3
Which on solving we will get that.
=0.125mol.
Now, the gram molecular mass of the Na2CO3:-
( 23 x 2) + 12 + (16 x 3).
= 46 + 12 + 48
=106 (g/mol).
So, the mass which is needed for giving 0.125 moles of the Na2CO3 will be:-
moles= mass / molar mass
Hence, we get that the mass = moles X molar mass.
=0.125 x 106.
=12.875 g.
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