Physics, asked by sreekritty, 8 months ago

What amount of
to be done to drive
a charge of
of 20mc if the potential difference is
40v?

Answers

Answered by dhirajjain1230
3

Explanation:

The total work done = energy transferred.

so, we might see the equation energy = voltage x charge, E = V * Q, written as,

work = voltage x charge, W = V * Q.

In this case, the charge is 4 mC, that is, 0.004 C and work done is 2 J.

Therefore, V=W/Q = 2/0.004 = 500 V.

Hence, the potential difference between two points if 2 J of work must be done to move a 4 mC charge from one point to another is 500 V.

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